dknitk
DHARMEDRA SAHU Staff answered 9 years ago
I saw below post on Stacktrace but did not get any proper solution.
I am coming across a strange thing. I have a number in binary in the form of string particularly “01001100”. But I am getting the exception mentioned above by executing the following code.
String s = “01001100”;
byte b = Byte.parseByte(s);
But why is it happening? Whereas in a byte we can store max no. upto 127 and min. upto -128.
And the decimal equivalent of the above number is 76 which is perfectly in the range.
The particular exception I am getting is as:
java.lang.NumberFormatException:Value out of range. value:01001100 radix:10
Is there any way to get rid of it. Yes and it is compulsory for me to use byte only as I am extracting the data stored in the image byte by byte only.
Thank you.
You can convert you string to Integer first and convert Integer to Byte. This will work wihout throwing any exception.
Byte byteValue = Integer.valueOf(“123453”);